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-rw-r--r--src/contrib/crypt/md5crypt.cpp233
1 files changed, 124 insertions, 109 deletions
diff --git a/src/contrib/crypt/md5crypt.cpp b/src/contrib/crypt/md5crypt.cpp
index 16b0235..8fb49a7 100644
--- a/src/contrib/crypt/md5crypt.cpp
+++ b/src/contrib/crypt/md5crypt.cpp
@@ -16,18 +16,20 @@
#include <string.h>
#include "md5.h"
-namespace md5 {
+namespace md5
+{
static unsigned char itoa64[] = /* 0 ... 63 => ascii - 64 */
- "./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
+ "./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
static void
to64(char *s, unsigned long v, int n)
{
- while (--n >= 0) {
- *s++ = itoa64[v&0x3f];
- v >>= 6;
- }
+ while (--n >= 0)
+ {
+ *s++ = itoa64[v&0x3f];
+ v >>= 6;
+ }
}
/*
@@ -39,109 +41,122 @@ to64(char *s, unsigned long v, int n)
char *
MD5Crypt(const char *pw, const char *salt)
{
- static char *magic = "$1$"; /*
- * This string is magic for
- * this algorithm. Having
- * it this way, we can get
- * get better later on
- */
- static char passwd[120], *p;
- static const char *sp,*ep;
- unsigned char final[16];
- int sl,pl,i,j;
- MD5_CTX ctx,ctx1;
- unsigned long l;
-
- /* Refine the Salt first */
- sp = salt;
-
- /* If it starts with the magic string, then skip that */
- if(!strncmp(sp,magic,strlen(magic)))
- sp += strlen(magic);
-
- /* It stops at the first '$', max 8 chars */
- for(ep=sp;*ep && *ep != '$' && ep < (sp+8);ep++)
- continue;
-
- /* get the length of the true salt */
- sl = ep - sp;
-
- MD5Init(&ctx);
-
- /* The password first, since that is what is most unknown */
- MD5Update(&ctx,(const unsigned char*)pw,strlen(pw));
-
- /* Then our magic string */
- MD5Update(&ctx,(const unsigned char*)magic,strlen(magic));
-
- /* Then the raw salt */
- MD5Update(&ctx,(const unsigned char*)sp,sl);
-
- /* Then just as many characters of the MD5(pw,salt,pw) */
- MD5Init(&ctx1);
- MD5Update(&ctx1,(const unsigned char*)pw,strlen(pw));
- MD5Update(&ctx1,(const unsigned char*)sp,sl);
- MD5Update(&ctx1,(const unsigned char*)pw,strlen(pw));
- MD5Final(final,&ctx1);
- for(pl = strlen(pw); pl > 0; pl -= 16)
- MD5Update(&ctx,final,pl>16 ? 16 : pl);
-
- /* Don't leave anything around in vm they could use. */
- memset(final,0,sizeof final);
-
- /* Then something really weird... */
- for (j=0,i = strlen(pw); i ; i >>= 1)
- if(i&1)
- MD5Update(&ctx, final+j, 1);
- else
- MD5Update(&ctx, (const unsigned char*)pw+j, 1);
-
- /* Now make the output string */
- strcpy(passwd,magic);
- strncat(passwd,sp,sl);
- strcat(passwd,"$");
-
- MD5Final(final,&ctx);
-
- /*
- * and now, just to make sure things don't run too fast
- * On a 60 Mhz Pentium this takes 34 msec, so you would
- * need 30 seconds to build a 1000 entry dictionary...
- */
- for(i=0;i<1000;i++) {
- MD5Init(&ctx1);
- if(i & 1)
- MD5Update(&ctx1,(const unsigned char*)pw,strlen(pw));
- else
- MD5Update(&ctx1,final,16);
-
- if(i % 3)
- MD5Update(&ctx1,(const unsigned char*)sp,sl);
-
- if(i % 7)
- MD5Update(&ctx1,(const unsigned char*)pw,strlen(pw));
-
- if(i & 1)
- MD5Update(&ctx1,final,16);
- else
- MD5Update(&ctx1,(const unsigned char*)pw,strlen(pw));
- MD5Final(final,&ctx1);
- }
-
- p = passwd + strlen(passwd);
-
- l = (final[ 0]<<16) | (final[ 6]<<8) | final[12]; to64(p,l,4); p += 4;
- l = (final[ 1]<<16) | (final[ 7]<<8) | final[13]; to64(p,l,4); p += 4;
- l = (final[ 2]<<16) | (final[ 8]<<8) | final[14]; to64(p,l,4); p += 4;
- l = (final[ 3]<<16) | (final[ 9]<<8) | final[15]; to64(p,l,4); p += 4;
- l = (final[ 4]<<16) | (final[10]<<8) | final[ 5]; to64(p,l,4); p += 4;
- l = final[11] ; to64(p,l,2); p += 2;
- *p = '\0';
-
- /* Don't leave anything around in vm they could use. */
- memset(final,0,sizeof final);
-
- return passwd;
+ static char *magic = "$1$"; /*
+ * This string is magic for
+ * this algorithm. Having
+ * it this way, we can get
+ * get better later on
+ */
+ static char passwd[120], *p;
+ static const char *sp,*ep;
+ unsigned char final[16];
+ int sl,pl,i,j;
+ MD5_CTX ctx,ctx1;
+ unsigned long l;
+
+ /* Refine the Salt first */
+ sp = salt;
+
+ /* If it starts with the magic string, then skip that */
+ if(!strncmp(sp,magic,strlen(magic)))
+ sp += strlen(magic);
+
+ /* It stops at the first '$', max 8 chars */
+ for(ep=sp;*ep && *ep != '$' && ep < (sp+8);ep++)
+ continue;
+
+ /* get the length of the true salt */
+ sl = ep - sp;
+
+ MD5Init(&ctx);
+
+ /* The password first, since that is what is most unknown */
+ MD5Update(&ctx,(const unsigned char*)pw,strlen(pw));
+
+ /* Then our magic string */
+ MD5Update(&ctx,(const unsigned char*)magic,strlen(magic));
+
+ /* Then the raw salt */
+ MD5Update(&ctx,(const unsigned char*)sp,sl);
+
+ /* Then just as many characters of the MD5(pw,salt,pw) */
+ MD5Init(&ctx1);
+ MD5Update(&ctx1,(const unsigned char*)pw,strlen(pw));
+ MD5Update(&ctx1,(const unsigned char*)sp,sl);
+ MD5Update(&ctx1,(const unsigned char*)pw,strlen(pw));
+ MD5Final(final,&ctx1);
+ for(pl = strlen(pw); pl > 0; pl -= 16)
+ MD5Update(&ctx,final,pl>16 ? 16 : pl);
+
+ /* Don't leave anything around in vm they could use. */
+ memset(final,0,sizeof final);
+
+ /* Then something really weird... */
+ for (j=0,i = strlen(pw); i ; i >>= 1)
+ if(i&1)
+ MD5Update(&ctx, final+j, 1);
+ else
+ MD5Update(&ctx, (const unsigned char*)pw+j, 1);
+
+ /* Now make the output string */
+ strcpy(passwd,magic);
+ strncat(passwd,sp,sl);
+ strcat(passwd,"$");
+
+ MD5Final(final,&ctx);
+
+ /*
+ * and now, just to make sure things don't run too fast
+ * On a 60 Mhz Pentium this takes 34 msec, so you would
+ * need 30 seconds to build a 1000 entry dictionary...
+ */
+ for(i=0;i<1000;i++)
+ {
+ MD5Init(&ctx1);
+ if(i & 1)
+ MD5Update(&ctx1,(const unsigned char*)pw,strlen(pw));
+ else
+ MD5Update(&ctx1,final,16);
+
+ if(i % 3)
+ MD5Update(&ctx1,(const unsigned char*)sp,sl);
+
+ if(i % 7)
+ MD5Update(&ctx1,(const unsigned char*)pw,strlen(pw));
+
+ if(i & 1)
+ MD5Update(&ctx1,final,16);
+ else
+ MD5Update(&ctx1,(const unsigned char*)pw,strlen(pw));
+ MD5Final(final,&ctx1);
+ }
+
+ p = passwd + strlen(passwd);
+
+ l = (final[ 0]<<16) | (final[ 6]<<8) | final[12];
+ to64(p,l,4);
+ p += 4;
+ l = (final[ 1]<<16) | (final[ 7]<<8) | final[13];
+ to64(p,l,4);
+ p += 4;
+ l = (final[ 2]<<16) | (final[ 8]<<8) | final[14];
+ to64(p,l,4);
+ p += 4;
+ l = (final[ 3]<<16) | (final[ 9]<<8) | final[15];
+ to64(p,l,4);
+ p += 4;
+ l = (final[ 4]<<16) | (final[10]<<8) | final[ 5];
+ to64(p,l,4);
+ p += 4;
+ l = final[11] ;
+ to64(p,l,2);
+ p += 2;
+ *p = '\0';
+
+ /* Don't leave anything around in vm they could use. */
+ memset(final,0,sizeof final);
+
+ return passwd;
}
}